Gravity seems holographic. What does that mean for reality?
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Gravity seems holographic. What does that mean for reality?
Unofficial Hacker News client; not affiliated with Y Combinator.
anigbrowl · · focus · HN ↗
The breathless tone of this article obscures rather than illuminates its subject. It sounds as if the author describes a box with some particles bouncing around inside, and every time a particle bounces off the wall of the box the outside glows briefly indicating the location and intensity of the collision. The author is amazed that by repeatedly measuring this, you can draw inferences about what's going on in the box.
I can't see what's 'outrageous' about this. You need a lower surface which registers information about activity inside a higher-dimensional volume, some way to accurately read that information, and the time/patience to repeat the measurement many times. Isn't this how radar works, or feeling your way around a pitch-dark room using only the 2-dimensional surface of your hands (or shins)? We know from computer science that you can mathematically encode any structure of arbitrary dimension into a binary tree. One might as well ask how it's possible that our complex 3 dimensional world can be contained in the flat surface of a mirror, film strip, or camera sensor.
pimlottc · · focus · HN ↗
senderista · · focus · HN ↗
dnautics · · focus · HN ↗
zmgsabst · · focus · HN ↗
senderista · · focus · HN ↗
dnautics · · focus · HN ↗
ReflectedImage · · focus · HN ↗
All the extra states you would assume the 3d volume can contain are actually a single state called Black Hole.
There is a limit to how much you can fill a 3d volume before it's a Black Hole basically.
api · · focus · HN ↗
I really think we live on the 3D event horizon of a 4D black hole, folks.
rbanffy · · focus · HN ↗
api · · focus · HN ↗
Since all the event horizons “touch” at N-1 dimensions I wonder if this is isomorphic with certain forms of string theory? Maybe there’s 11 levels of holes?
BTW this isn’t my idea. There’s papers on black hole cosmology. You can make the math work but no way to test it. Yet?
mjanx123 · · focus · HN ↗
tclancy · · focus · HN ↗
junkblocker · · focus · HN ↗
rbanffy · · focus · HN ↗
b800h · · focus · HN ↗
nbernard · · focus · HN ↗
geocar · · focus · HN ↗
nextaccountic · · focus · HN ↗
I don't think it has been experimentally verified or anything
brotchie · · focus · HN ↗
bell-cot · · focus · HN ↗
Quibble: A black hole still has a charge, mass, momentum vector, and spin vector. Which, yes, still vastly reduces the number of states needed on the surface of the enclosing container.
thaumasiotes · · focus · HN ↗
How can that be? Don't different black holes have different masses?
ReflectedImage · · focus · HN ↗
For exactly how that works, I'm a Comp Sci not a Physicist.
thaumasiotes · · focus · HN ↗
Huh? If the correlation between density and mass is perfect, that means two things:
1. There is an upper limit on the mass of the black hole, set by the volume of the box containing it.
2. The black hole's possible mass and density occupy a one-dimensional space and not a two-dimensional space.
Now, it appears to be true that the (possibly nonlinear) correlation between mass and density is perfect; for any mass a black hole can have only one density. But that doesn't make the space of possibilities finite. It certainly won't make it into a single point. And in fact black holes appear to have three independent physical dimensions: their mass, their electric charge, and their spin.
[deleted] · · focus · HN ↗
[deleted]
__david__ · · focus · HN ↗
idiotsecant · · focus · HN ↗
oulipo · · focus · HN ↗
Which is exactly the part that "defies common sense" and is intersting
Alex3917 · · focus · HN ↗
Does it? Isn't this basically the same as how cellular companies can figure out exactly where someone is calling from as long as their phone is pinging 3+ towers? Just connect the towers into a box and you have the same result.
EthanHeilman · · focus · HN ↗
zelphirkalt · · focus · HN ↗
EthanHeilman · · focus · HN ↗
anigbrowl · · focus · HN ↗
rbanffy · · focus · HN ↗
larksimian · · focus · HN ↗
You still have less information than if you could observe the full 3d spatial volume over time, because presumably you won't know in perfect detail qnd precision what all the particles are doing internally?
Or does it not work like this?
thaumasiotes · · focus · HN ↗
Interestingly enough, I believe there is a result that space-filling curves cannot be one-to-one, but the implication there is just that, by virtue of the continuity of the one-dimensional curve, it contains more points than the two-dimensional space that it fills.
calf · · focus · HN ↗
yshklarov · · focus · HN ↗
"Put a box around any region of space (space-time, really, but I’m going to drop time throughout this essay for ease of visualization, as physicists often do). The holographic principle asserts that no matter what’s going on inside — from gas molecules pinging around to black holes colliding — you can decipher the entire contents of the box just by repeatedly measuring points on the surface."
Well, if we're bounding a region of space-time then, in a purely classical universe governed by deterministic ODEs or PDEs, the statement reduces to a triviality: having information about the boundary amounts to knowing all boundary conditions. Of course I understand that this isn't really the statement of the holographic principle, but the article's formulation is rather underwhelming.
ridiculous_fish · · focus · HN ↗
So classically you cannot decipher the entire contents of the box just from its surface!
bugake · · focus · HN ↗
If the field is always radial, the charge can only be in the center, by symmetry. A different distribution of charges will not produce a radial field on the surface, even if it has the same integral.
yshklarov · · focus · HN ↗
peter_d_sherman · · focus · HN ↗
Space filling curves with three dimensions could potentially provide us with some clues:
<a href="https://en.wikipedia.org/wiki/Z-order_curve" rel="nofollow">https://en.wikipedia.org/wiki/Z-order_curve
"In mathematical analysis and computer science, functions which are Z-order, Lebesgue curve, Morton space-filling curve,[1] Morton order or Morton code map multidimensional data to one dimension while preserving locality of the data points (two points close together in multidimensions with high probability lie also close together in Morton order)."
Also, to answer the question, potentially Octrees might be interesting to research:
<a href="https://mathworld.wolfram.com/Octree.html" rel="nofollow">https://mathworld.wolfram.com/Octree.html
"An octree is a rooted tree that represents a three-dimensional region by recursively subdividing it into eight congruent, axis-aligned cuboids, usually cubes (Meagher 1982, Samet 1990). Each internal node represents a spatial cell and has eight children, one for each octant of the cell. A tree leaf represents a cell that is not subdivided further."
But, since "a picture is worth one thousand words":
<a href="https://www.google.com/search?q=octree&udm=2" rel="nofollow">https://www.google.com/search?q=octree&udm=2
Another thing to consider is that according to the Knuth Transform (aka Left-Child Right-Sibling (LCRS) representation), apparently any k-ary tree (Octree = 8-ary tree) can apparently be converted into a Binary Tree without losing information:
<a href="https://en.wikipedia.org/wiki/Left-child_right-sibling_binary_tree" rel="nofollow">https://en.wikipedia.org/wiki/Left-child_right-sibling_binar...
So, is there a 1D (or 2D) representation for 3D reality?
Well, I personally don't know!
What I do know is that a certain popular rock group sang the following lyric in one of their popular rock songs, back in 1999:
"Space may be the final frontier -- but it's made in a Hollywood basement..."
-The Red Hot Chili Peppers, "Californication"
So, you decide! :-)
cubefox · · focus · HN ↗
> One might as well ask how it's possible that our complex 3 dimensional world can be contained in the flat surface of a mirror, film strip, or camera sensor.
No this is different. You can't classically encode an arbitrary 3D world on a camera sensor without losing information. It can only create a 2D projection of surfaces. It can't look inside opaque objects. Countless distinct 3D objects could correspond to one an the same 2D projection. There are actually many examples of optical illusions which show that a 2D image can be ambiguous with regards the 3D space it represents.
rbanffy · · focus · HN ↗
kybernetikos · · focus · HN ↗
thaumasiotes · · focus · HN ↗
You could ask, but that isn't possible, so the question is of dubious value. There are many states of the 3-dimensional world that will produce identical images in the surface of a mirror.
bugake · · focus · HN ↗
Inside the box, there may be one rat, a galaxy, a nuclear bomb, or whatever thing you can imagine, and still you know exactly the change in stored energy. It only depends on what happened on the surface of the box.
Also, when you solve a differential equation, you need the contour conditions. The contour completely determines what happens inside.
oulipo · · focus · HN ↗