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Coulomb's law remains tricky to test at home

29 points · 23 comments · surprisetalk

  1. nh23423fefe · · focus · HN ↗
    > But it's not at all obvious to me why the exponent a is 1 in nature

    i think we can rule out any exponent just by dimensional analysis if you allow powers of q, then K has ambiguous units. Same reason you cant exponentiate unitful quantities

    More specifically I think we can rule out even exponents by anti-symmetry of charge. That is q^2n = (-q)^2n which know is ruled out by experiment.

    1. NooneAtAll3 · · focus · HN ↗
      you have free constant k in front of the equation

      any dimensional analysis gets consumed by its unknown dimensionality

      ---

      > q^2n = (-q)^2n which know is ruled out by experiment.

      doesn't mean equation can't be using absolute values ("number of electrons/protons") and just applying needed sign at the end

      1. nh23423fefe · · focus · HN ↗
        K isn't free, its bound obviously

        it can't use absolute values, you can't write that equation down

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