Thread

1. JoshTriplett · 1789746575 · focus · HN ↗

   > When both conditions are met, the loop body is replaced with a call to std::this_thread::yield().

   Insert screaming here.

   An infinite loop, with no library calls whatsoever, gets a system call inserted. That's a horrible surprise waiting to happen.

   The entire concept of the "forward progress guarantee" is broken. An infinite loop should compile to an infinite loop. Nothing more, nothing less.

   1. marcosdumay · 1789751761 · focus · HN ↗

      I don't understand your problem. Did you expect your C++ program to get uninterrupted access to the computer? What progression do you think isn't happening there?

      I think you are misinterpreting that. That phrase unambiguously says the loop is preserved on the final binary.

      1. rcxdude · 1789777771 · focus · HN ↗

         Any program in an OS only gets as much resources allocated to it as the OS allows (OK, in any general-purpose OS written in the past few decades). sched_yield() doesn't actually reduce that allocation in most cases, anyhow: in fact it has a higher chance of increasing the resources that the thread uses spinning in a loop because it's gonna be thrashing the scheduler as well.

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