Thread

1. JoshTriplett · 1789746575 · focus · HN ↗

   > When both conditions are met, the loop body is replaced with a call to std::this_thread::yield().

   Insert screaming here.

   An infinite loop, with no library calls whatsoever, gets a system call inserted. That's a horrible surprise waiting to happen.

   The entire concept of the "forward progress guarantee" is broken. An infinite loop should compile to an infinite loop. Nothing more, nothing less.

   1. usefulcat · 1789754439 · focus · HN ↗

      Yeah, I don't get it either. Like if I wanted to call std::thread::yield() inside an infinite loop, I could, you know, just do that myself?

      An obvious question (that TFA does not address) is, why is the forward-progress guarantee needed? Since that is the ostensible justification for this new invisible behavior.

      1. [deleted] · 1789766723 · focus · HN ↗

         [deleted]

Unofficial Hacker News client; not affiliated with Y Combinator.